Amazing logic game
The game was designed to learn and at the same time have fun solving it. I believe puzzles and mind games are not loved by everyone.
This game known as River Crossing IQ is fun because of its animated character and is suitable for all.
River Crossing IQ
Solutions to solve River Crossing IQ game
It’s fun to play. Here are the first six levels, also see second six levels of River Crossing IQ Game
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Solution of six levels of River Crossing IQ.
There are more levels, many people think this game has only fixed levels and no option to select any other level. More levels appear after solving them.
How to solve River Crossing IQ just to bring interest on solving. Most people give up without trying. When unable to solve they put negative comments on game reviews and post replies.
Let us start, by keeping your Android phone ready. Playing a logic game is fun.
Help the man on the boat move Wolf, Sheep and Cabbage
Help the man on the boat move Wolf, Sheep and Cabbage
Logic 1: Help the man on the boat move Wolf, Sheep, and Cabbage across the river. Each move attaches to only one animal or object, when the man is not nearby, the Wolf will eat the Sheep, and the Sheep will eat the Cabbage.
Solution: Here boat can carry two persons/objects at a time. The sailor is sailing and he will be there always, so the boat can sail back without any person/object.
Step 1: Take the Sheep first and back.
Step 2: Pick a Wolf and drop across the river. Sail back with the Sheep.
Step 3: Drop the Sheep and take the Cabbage.
Step 4: Back alone and take the Sheep.
Take a mother and 5 sons
Take a mother and 5 sons across the river
Logic 2: Take a mother and 5 sons across the river. Knowing that the boat can carry up to 3 people, only the mother can sail. When the mother is absent, 1-year-old older or younger kids will fight the other.
Solution: Here boat can carry up to 3 people and one will be always on the boat with two kids at a time. Cannot leave kids who are 1 year old older or younger. This means 6-7, 7-8, 8-9, and 9-10 will fight when the mother is absent.
So 6, 8, and 10-year-old kids can be left. In the same, we have to drop them across the river.
Let the first shore is A and the second is B.
Step 1: Take 7 and 9 first and drop 9 to the shore B. Mother back with 7.
Step 2: Drop 7 on shore A. Pick 6 and 8 to shore B, back with 9.
Step 3: Pick 10 to shore B.
Step 4: Now pick 7 and 9 from shore A to Shore B.
Help the man on the boat move Sheep, Buffalo and Tiger
Help the man on the boat move Sheep, Buffalo, and Tiger across the river
Logic 3: Help the man on the boat move Sheep, Buffalo, and Tiger across the river. Each move attaches to only one animal, when the man is not nearby, the tiger will eat the Sheep and 2 tigers will eat 1 Buffalo.
Solution: One animal at a time. Can’t leave a Sheep with a tiger and a Buffalo with two tigers.
Let first shore = A
Second shore = B
Step 1: Take Sheep first to shore B and back alone.
Step 2: Take Tiger now to shore B and back with the Sheep to shore A.
Step 3: Take another Tiger from shore A to shore B and back alone.
Step 4: Now a Buffalo from shore A to shore B and back with a Tiger to shore A.
Step 5: Take the Sheep from shore A to shore B and back with the Tiger from shore B to shore A.
Step 6: Take Buffalo from shore A to shore B. Back alone to shore A.
Step 7: Take a Tiger from shore A to shore B and take the Sheep to shore A.
Step 8: Take the tiger from shore A to shore B and back to take the Sheep from shore A to shore B.
Help the 3 Cannibals and 3 Missionaries move to the other side of the lake
Help the 3 Cannibals and 3 Missionaries move to the other side of the lake
Logic 4: Help the 3 Cannibals and 3 Missionaries move to the other side of the lake. If the number of Cannibals is larger than the number of Missionaries on either side of the lake, the Missionaries will be eaten.
Solution: The number of Cannibals and Missionaries should be equal or the number of Missionaries could be greater than the number of Cannibals.
First shore = A
Second shore = B
Step 1: Take two Cannibals to shore B, and drop one and another back to shore A.
Step 2: Take last Cannibal to shore B and the third go back to shore A and stays.
Step 3: Now two Missionaries to shore B, drop them. One Cannibal and one Missionary sail back to shore A.
Step 4: Drop Cannibal to shore, pick one Missionary, and sail (two missionaries are sailing now) to shore B.
Step 5: Drop two Missionaries, and Cannibal goes back to shore A.
Step 6: Now two Cannibals can sail the first time and the second time the last Cannibal.
Help a family of 5 people move across the river by boat
Help a family of 5 people move across the river by boat
Logic 5: Help a family of 5 people move across the river by boat, and the boat is capable of a maximum of 2 people carrying capacity. The time for traveling of each person in turn is 1 second, 3 seconds, 6 seconds, 8 seconds, and 12 seconds. If two people both go on the boat, the boat will travel at the speed of the slower person. In 30 Seconds please bring the whole family across the river.
Solution: At this level, we have to maintain the traveling time. 5 people will take time as mentioned above, 8 and 12 seconds are the highest time. We have to reduce it from our calculation.
If they both travel, the boat will travel at the speed of a slower person (12 seconds), boat can back without any person. So one (8 seconds) has to back and carry another person. Here it takes 12+8=20 seconds, where we have only 30 seconds.
See the time for all people and add them 1+3+6+8+12=30. We have limited time to move all these five people.
First shore = A
Second shore = B
Step 1: Take 1 and 3 first to shore B 1 stays there and 3 go back to shore A.
Step 2: 3 stays, 12 and 8 go to shore B. Both 12 and 8 stay on shore B, and 1 go back to shore A.
Step 3: 1 and 3 go to shore B, 3 stays, and 1 back to shore A.
Step 4: Now 1 and 6 go to shore B.
Three couples go picnic together
Three couples go picnic together
Logic 6: Three couples go picnic together. They must move across a river with one boat carrying a maximum of 2 people. Help them move across the river, provided that husbands would not allow their wives to go with another man without their presence there.
Solution: Husbands would not allow their wives to go with another man and the husband must present to another side. Ladies can travel together, men can travel together. Ladies/lady can’t be left with another man unless their husbands are present.
How we start, same way finish it.
Red man and wife – RM/RW
Blue man and wife – BM/BW
Yellow man and wife – YM/YW
First shore = A
Second shore = B
Step 1: First of all start with ladies. Suppose RW and YW, go to shore B and RW stays, and YW go back to shore A.
Step 2: YW and BW travel to shore B. BW stays and YW goes back to their husband on shore A.
Step 3: Now men travel to wives, RM and BM to shore B.
Step 4: RM stays on shore B, BM with BW back to shore A.
Step 5: BW stays on shore A. BM and YM travel to shore B.
Step 6: All three men stay on shore B. RW travels to shore A.
Step 7: RW and BW travel to shore B. RW back to shore A.
Step 8: Now RW and YW travel to shore B.
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